Can anyone please tell me what the potential combinations of picks are at the start in 1v1 with 3 picks each. I think that information would be handy but I just can't get my head round it to work it out.

If my opponent doesn't pick any of my first three obviously I get my first three...thats actually where i get stuck trying to work it out although somewhere in the back of my head that not all combinations are possible.

Combination in what respect? How many different ways can you get awarded territories from your six selections based on how your opponent picks?

Can't find it, but there was another thread with a couple pages of debate on this very subject.

Well, picks, as I understand them, are assigned to you as what is the highest pick available.

So, assuming you have the following table:

Territory / Player A Rank / Player B Rank
A / 1 / 3
B / 2 / 4
C / 3 / 1
D / 4 / 5
E / 5 / 2
F / 6 / 6

So, Assuming A get's first Pick, he gets his first 1 available: So A.

Then B gets his highest two avail: C, E,

Then A gets his two highest: (already has A), so he gets B and D because C was already taken.

Then B gets his last pick, F.

So, at the end of the day, Player A gets: A, B, C (or his 1, 2, 4 picks) and B gets C, E, F, or his 1, 2 and 6 picks.

But if Player B gets his to pick first, then the selections goes:
Player B: C, E, D (1, 2, 5)
Player A: A, B, F (1, 2, 6)

This just assumes each player picks the same exact territories.

I tried looking through the archives but couldnt find anything. Thanks for that John but what I meant may be better explained like this...???

123
124
125
126
134
135
136
145
146
156
234
235
236
245
246
256
345
346
356
456

Clearly not all of the above combinations are possible (for example 456). Was just wondering if someone could point out which ones. Even better if they could explain how they worked it out.

All possible since you don't know their order:
123
124
125
126
134
135
136
145
146
156
234
235
236
245
246
256

Not possible as you'd get 1 or 2:
345
346
356
456

Most of the top ones are possible if they pick 1st (not overlapping with your picks), then you get two picks and they get two picks. Allows for things like 1,2,6.

So, 16 possible outcomes from your picks. Does that seem right?

Can't get 245, 246 or 256. Only way you get stuck with your 2 is if opponent gets first pick. Should that happen, you automatically get the next two picks which would be 2-3.

I also don't believe you can get 146 or 156. If you get first pick then you are guaranteed 4-5 at worst. If you get second pick then you are guaranteed 2 of the top 3.

123
124
125
126
134
135
136
145
234
235
236

Those are the only 11 possible combinations. Richard is right in the post above this one that those 5 he mentioned, are impossible. I bet if I looked at all my games, I could find an example of each one of these combinations, although some are much more common of course. No others are possible.

I had to do it , lol.

Yep, jsa listed all th combinations I can think of. Try to get 125 or 126, when you do, you most probably will win.

Warlight:

Serious Business

^Lmao

There are 11 possibles. Got it. Everyone should know that. Very handy.

So who can do the same for a 4 pick each scenario?! No prize for the winner.

1234
1235
1236
1237
1238
....

I have got you started lol.

Handy indeed. If all of the picks overlap, one player will get 145 and the other 236.

1234
1235
1236
1237
1238
1245
1246
1247
1248
1256
1257
1258
1267
1345
1346
1347
1348
1356
1357
1358
1367
1456
1457
1458
1467
2345
2346
2347
2356
2357
2367

I don't play 4 pick games much at all so I'm not 100% sure these are right. So if anyone can add others, please explain how it is possible and add it to this list. Sam e for taking any away. I think this is almost copmletely accurate though and it might be.

1467 does not seem possible:

Either you get 1st pick, then it is:
you: 1
Player B: 2 + 3
you: 4 + 5
Player B: 6 + x
you: 7

-> 1457

Or you get 2nd pick, then it is:
Player B: 2 or 3
you: 1 + (3 or 2)
Player B: 4 + 5
you: 6 + 7

-> 1367 or 1267

What about 2v2 (assuming you have same picks)?

2v2, 2 picks each player, assuming you have coordinated your picks and do not overlap with your teammate (though this might be desireable in some occasions):

Players in order A, B, b, a - a, b, B, A (spot the elk!)

with A + a = Team 1 and B + b = Team 2

(IIRC it is not possible anymore for one team to get the first 2 picks, so an order of A, a, B, b should be impossible?)

Player A (=1st pick) might end up with:
1 2 (0 overlapping picks)
1 3 (1 op with B or b)
1 4 (2 op with B and/or b)
1 5 (3 op with B and b)
1 6 (4 op with B and b)

Player B (=2nd pick):
1 2 (0 op)
1 3 (1 op with a)
1 4 (2 op with a)
2 3 (1 op with A)
2 4 (2 op with A and a)
2 5 (3 op with A and a)

Player b (=3rd pick)
1 2 (0 op)
1 3 (1 op with a)
1 4 (2 op with a)
2 3 (1 op with A)
2 4 (2 op with A and a)
2 5 (3 op with A and a)

Player a =(4th pick)
1 2 (0 op)
2 3 (1 op with B or b)
3 4 (2 op with B and b)

-> possible outcome:
1 2
1 3
1 4
1 5
1 6
2 3
2 4
2 5
3 4

someone else do it for teammates with overlapping picks :-)

2v2 with both teams doing mirror picks gives the same results as a 4 pick 1v1. One player will get the first and last picks, while the other player will get the two in the middle.

Whats the best 3 starting points in SMALL MEDIUM AND BIG EARTH _ bold